2x(4x-3)=8x^2-1

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Solution for 2x(4x-3)=8x^2-1 equation: 


Simplifying
2x(4x + -3) = 8x2 + -1

Reorder the terms:
2x(-3 + 4x) = 8x2 + -1
(-3 * 2x + 4x * 2x) = 8x2 + -1
(-6x + 8x2) = 8x2 + -1

Reorder the terms:
-6x + 8x2 = -1 + 8x2

Add '-8x2' to each side of the equation.
-6x + 8x2 + -8x2 = -1 + 8x2 + -8x2

Combine like terms: 8x2 + -8x2 = 0
-6x + 0 = -1 + 8x2 + -8x2
-6x = -1 + 8x2 + -8x2

Combine like terms: 8x2 + -8x2 = 0
-6x = -1 + 0
-6x = -1

Solving
-6x = -1

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '-6'.
x = 0.1666666667

Simplifying
x = 0.1666666667

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